Challenge · Negative Numbers

No calculator9 marks

These problems use negative numbers in calculations, substitution, temperature contexts and BIDMAS. A worked example shows how to start; hints are at the foot.

Worked example: how to start
The temperature is $-4\,^\circ$C. It rises by $9\,^\circ$C. Work out the new temperature.
A rise means add: $-4+9$.
From $-4$, going up $9$ passes zero.
$-4+9=5\,^\circ$C.
1Work out $-7+12$.[1 mark]
Answer:
2Work out $(-3)\times(-8)$.[1 mark]
Answer:
3The temperature falls from $3\,^\circ$C to $-5\,^\circ$C. Work out the fall in temperature.[2 marks]
Answer:
4Work out the value of $2a-b$ when $a=-3$ and $b=-5$.[3 marks]
Answer:
5Work out $-2+3\times(-4)$.[2 marks]
Answer:
Extension: Work out the value of $a^2-2a$ when $a=-4$.
Stuck? Hints (don't peek unless you need to)1. Start at $-7$ on a number line and move $12$ to the right.2. Same signs give a positive.3. The fall is the DIFFERENCE: $3-(-5)$.4. Substitute carefully, then deal with the double signs.5. BIDMAS: do the multiplication first.

Solutions & mark scheme · Negative Numbers

Total: 9 marks

Award the marks shown for each correct step; many of these have more than one valid route, so give method marks for any correct working.

1Work out $-7+12$.[1]
Model solution
$-7+12=5$.
Answer: $5$
Marks
1$=5$
2Work out $(-3)\times(-8)$.[1]
Model solution
Same signs $\to$ positive: $(-3)\times(-8)=24$.
Answer: $24$
Marks
1$=24$
3The temperature falls from $3\,^\circ$C to $-5\,^\circ$C. Work out the fall in temperature.[2]
Model solution
Fall $=3-(-5)=3+5=8\,^\circ$C.
Answer: $8\,^\circ\text{C}$
Marks
1Uses $3-(-5)$
1$=8\,^\circ$C
4Work out the value of $2a-b$ when $a=-3$ and $b=-5$.[3]
Model solution
$2a-b=2(-3)-(-5)$.
$=-6+5$.
$=-1$.
Answer: $-1$
Marks
1$2(-3)=-6$
1$-(-5)=+5$
1$=-1$
5Work out $-2+3\times(-4)$.[2]
Model solution
Multiply first: $3\times(-4)=-12$.
$-2+(-12)=-2-12=-14$.
Answer: $-14$
Marks
1$3\times(-4)=-12$
1$=-14$
Extension
$a^2=(-4)^2=16$ (a square is always positive).
$-2a=-2\times(-4)=+8$.
So $a^2-2a=16+8=24$.
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